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Date: 2010-04-14 01:52 pm (UTC)
Why, in "Blues in E", do you have complex chords in bars 9 and 10 when the others are all just two strings (and all of "Blues in G" is just two strings per chord)? Surely a simple x-2-4-x-x-x for the B and back to x-0-2-x-x-x for the A will suffice. (Basically they are all open 5th (alternating with 6th) chords apart from those two.)
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